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Diagonals of a parallelogram ABCD intersect at O. If ∠BOC = 90^° and ∠BDC = 40^°. Then ∠OAB is : (1) 90^° (2) 40^° (3) 60^° (4) 50^°
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In the adjoining figure, ABCD is a parallelogram. P is a point on BC such that BP : PC = 1 : 2 and DP produced meets AB produced at Q .
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ABCD is a parellelogram, AB is produced to E such that AB=BE. Prove that ED bisects BC.
ABCD is a parallelogram and ∠DAB=60^°. If the bisector AP and BP of the angles A and B respectively meet at P on CD, prove that P is the mid point of
ABCD is a parallelogram and the bisector of angle A bisects BC at X. Prove that AD =2AB
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In a parallelogram ABCD ,diagonal BD bisects one angle . Prove that the diagonal 1. bisects the other angle 2. ABCD is a rhombu
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